In the following triangle theta=60.Find the values of the angles of the angles B and B'

  A.  B = 64.13° or B' = 115.87°

Step-by-step explanation:

The given angle is opposite the shortest of the given sides, so there are two possible solutions using the Law of Sines. Either way, we have ...

  sin(B)/16 = sin(θ)/15.4

  B = arcsin(16/15.4·sin(60°)) ≈ arcsin(0.899767)

  B = 64.13° or B' = 180° -64.13° = 115.87°

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.