Mathematics, 08.06.2020 06:57 loistaylor1819
10=0.0048(×_50)^2+6The cable is 10 feet above the roadway at horizontal distances of about 4ft and 96 ft. 13ft and 87ft. 21ft and 79 ft. 48ft and 52 ft from the left support
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10=0.0048(×_50)^2+6The cable is 10 feet above the roadway at horizontal distances of about 4ft and 9...
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