Carlos' school is selling tickets to a spring musical. On the first day of ticket sales the school sold 6 adult tickets and 12 student tickets for a total of $204. The school took in $79 on the
second day by selling 5 adult tickets and 3 student tickets. What is the price each of one adult
ticket and one student ticket?

Adult ticket = $8

Student ticket = $13

Step-by-step explanation:

Hi, to answer this we have to write a system of equations (sales equations)

6x + 12y =204 (first day)

5x +3y =79 (second day)

Where x is the price of each adult ticket and y is the price of each student ticket.

If we multiply the second equation by 4 , and subtract the first equation to the second equation:

20x +12y =316

-

6x + 12y =204

14x = 112

Solving for x:

x =112/14  

x = 8  

Substituting x=8 on any equation:

5x +3y =79

5(8)+3y =79

40+3y =79

3y =79-40

3y = 39

y =39/3

y = 13

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.