Oliver is trying to solve the following equation by completing the square. x2−32x+31=0 Here are the steps Oliver used to complete the square. Original equation: Line 1: Line 2: Line 3: Line 4: Line 5: Line 6: x2−32x+31x2−32xx2−32x+32(x−16)2(x−1 6)2−−−−−−−−√x−16x0−31−31+3211–√±115 and x=17 Oliver did not get the correct solutions. Which line contains Oliver's first mistake?

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

60%

probably .5

i can on others if necessary.