If xy>0, then the points of P(x, y) lies...

If xy>0, then the points of P(x,y) lies in Quadrant I and III

According to the given condition;

This means that the product of x and y is a positive number.

Hence, either both x and y-coordinates are positive or are both negative

Hence, only points in the Quadrant I have positive x and y coordinates Or Quadrant III in which case all x and y values are negative.

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In Quadrant I or III

Step-by-step explanation:

We know if the sign was not showing closed inequality facing other way

xy < 0 would be in the 2nd or 4th quadrant.

If xy = 0  then either xy or both are on the x or y axis

But if xy>0 then they are in quadrant I or III

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

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the practice of taking someone else's work or ideas and passing them off as one's own.

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