A horizontal line has points J, K, L. A line extends from point K up and to the right to point M. Angle J K M is (10 y + 6) degrees and angle M K L is (8 y minus 6) degrees What is the value of y?
y =

Find the following angle measures.
mAngleJKM = °
mAngleMKL = °

The found values are:

y = 10

<JKM = 106°

<MKL = 74°

Step-by-step explanation:

(See the diagram attached)

As JKL is a straight horizontal line, angle measure from JK to KL is 180°.

We can see in the diagram that line KM is dividing this angle of 180° into 2 unequal parts.

Which means that the sum of <JKM and <MKL is equals to 180°.

Mathematically, it can be written as:

Substitute the values of both angle to solve the equation:

Put in the formulas of both angle to find their values:

<JKM = 10y + 6

<JKM = 10(10)+6

<JKM = 106°

<MKL = 8y - 6

<MKL = 8(10)-6

<MKL = 74°

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb