1. If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and the sum of the ages of all 3 is 147 years, what is the age difference between oldest the
youngest?
Ans: years

2. The HCF of two numbers is 11, and their L. C.M is 368. If one number is 64, then the other
number is ….

1) 48 years.

2) Question incorrect.

11 isn't a factor of 64, and 368 isn't a multiple of 64. 11 also isn't a factor of 368, hence, it would be impossible to find the unknown second number with all of these false information in the question.

Step-by-step explanation:

Let the ages of Kissi, Esinam and Lariba be x, y and z respectively.

Ratio of the ages of Kissi and Esinam is 3:5

x:y = 3:5

(x/y) = (3/5)

5x = 3y

x = (3y/5) (eqn 1)

Ratio of the ages of Esinam and Lariba is 3:5

y:z = 3:5

(y/z) = (3/5)

5y = 3z

z = (5y/3) (eqn 2)

The sum of their 3 ages is 147

x + y + z = 147 (eqn 3)

Substituting the values of x and z from eqn 1 and 2 into eqn 3, we have

(3y/5) + y + (5y/3) = 147

(49y/15) = 147

y = (147×15/49) = 45.

x = (3y/5) = (3×45/5) = 27

z = (5y/3) = (5×45/3) = 75

The ages of Kissi, Esinam and Lariba are then 27, 45 and 75 respectively.

The difference in the ages of the oldest amf the youngest is thus, 75 - 27 = 48 years.

2) This question seems to be faulty and incorrect as 11 isn't a factor of 64, and 368 isn't a multiple of 64. 11 also isn't a factor of 368, hence, it would be impossible to find the unknown second number with all of these false information in the question.

Hope this Helps!!!

y/x=18

step-by-step explanation: