the average mark of candidates in an aptitude test was 138.5 with a standard deviation of 10.6. three scores extracted from the test are 178,122,100.what is the average of the extracted scores that are extreme value

The average of the extracted scores  = 133.33

Step-by-step explanation:

Given data the average mark of candidates in an aptitude test was 138.5 with a standard deviation of 10.6

mean of the aptitude test = 138.5

Standard deviation of the  aptitude test = 10.6

Given three scores extracted from the test are 178,122,100

The average of the extracted scores = ∑x / n

The average of the extracted scores

                                        =

                                        = 133.33

Final answer:-

The average of the extracted scores  = 133.33

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: