What are the coordinates of the center of a circle whose equation is (x+1)^2+y^2=100?

The center is (-1,0) and the radius is 10

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k)^2 = r^2

where the center is (h,k) and the radius is r

(x+1)^2+y^2=100

(x - -1)^2+(y-0)^2=10^2

The center is (-1,0) and the radius is 10

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5

the solution is 12x-6y