What is the solution to this system of linear equations? 2x + 3y = 3 7x – 3y = 24 (2, 7) (3, –21) (3, –1) (9, 0)

2x +3y=3

7x-3y=24

solve the above equations

2x+3y=3

+7x-3y=24

9x=27

x=27/9

x=3

substitute the value of x in 2x+3y=3

2(3)+3y=3

6+3y=3

3y=3-6

3y=-3

y=-3/3

y=-1

so the solution is

{x=3,y=-1}

answer: give more info

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°