A shopper pushes a grocery cart with a force F of 55N downward and to the right, as shown in the figure below. The angle the handle makes with the horizontal is 42°, and the cart is moved 7m. Find the work W done, in joules J. Do not round any intermediate computations, and round your answer to the nearest hundredth. w= j

first one because it can't have a fraction in it

step-by-step explanation:

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7

the result can be shown in both exact and decimal forms.

exact form; 76 · 75, 4911, 4935, 711, 735

decimal form: 5700, 4911, 4935, 711, 735