The function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=69 and s(6)=141.Find the average velocity of the object over the interval of time [2,6 ].

The average velocity of the object over the interval of time [2,6] is of 18 units of distance per unit of time.

Step-by-step explanation:

The average velocity can be calculated as the division of the position change by the time change.

Find the average velocity of the object over the interval of time [2,6 ].

6 - 2 = 4 units of time (t, min,...)

s(6) = 141, s(2) = 69

141 - 69 = 72 units of distance(m, km...)

72/4 = 18 u.d./u.t.

The average velocity of the object over the interval of time [2,6] is of 18 units of distance per unit of time.

step-by-step explanation:

just plug in each number for x and see which ones work and don't

measurement of the swimming pool is given as = 7 yards 4.79 feet

first we will convert this to yards only.

1 foot = 0.33 yards

so, 4.79 feet = yards

so total yards are = yards

now we will convert this in meters.

1 yard = 0.914 meters

8.580 yards = meters

0.842 m = 0.842*100 = 84.2 cm

this becomes 7 meters and 84.2 cm

hence, the pool is 7 meters and 84.2 cm wide.