Choco pies are cookies made from chocolate (c), sugar (s), and flour (. Chocolate costs $5 per pound, sugar costs $3 per pound, and flour costs $2 per pound. You spend $50 on 18 pounds of food and buy twice as much flour as

sugar

Calvin wants to invest $12,000 in deposits. For tax purposes, he wants his total interest to be $600. He wants to put

$1000 more in a 2-year deposit than in a l-year deposit and invest the rest in a 3-year deposit. How much money

should he invest in each deposit?

Number of Years

Rate

2.0%

5.09

6.0%

1-year: $2200, 2-year: $3200, 3-year: $6600

1-year: $4000, 2-year: S5000, 3-year: $3000

1-year: S3200, 2-year: $4200, 3-year: $4600

1-year: $1000, 2-year: S2000, 3-year: $9000

Question :

justinapace7446

Yesterday

Mathematics

High School

+5 pts

Choco pies are cookies made from chocolate (c), sugar (s), and flour (. Chocolate costs $5 per pound, sugar costs

$3 per pound, and flour costs $2 per pound. You spend $50 on 18 pounds of food and buy twice as much flour as

sugar

Calvin wants to invest $12,000 in deposits. For tax purposes, he wants his total interest to be $600. He wants to put

$1000 more in a 2-year deposit than in a l-year deposit and invest the rest in a 3-year deposit. How much money

should he invest in each deposit?

Number of Years

Rate

2.0%

5.0%

6.0%

1-year: $2200, 2-year: $3200, 3-year: $6600

Step-by-step explanation:

Assume y = Amount invested for 1 year.

y + 1000 = investment amount for 2 years

12000 - (y + y + 1000 ) = amount invested for 3 years

11000 - 2y = amount invested for 3 years

Total interest

Multiplying each by its corresponding rate

(0.02 × y) + (0.05 × (y+1000)) + (0.06 × (11000-2y)) = 600

0.02y + 0.05y + 50 + 660 - 0.12y = 600

-0.05y + 710 = 600

-0.05y = 600 - 710

-0.05y = - 110

y = 2200

Therefore first year = y = $2200

Investment for 2 years =y + 1000 = 2200 + 1000 = $3200

Investment for 3 years = 11000 - 2y = (11000 - (2*2200)) = (11000 - 4400) = $6600

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204