A standard six-sided die is rolled three times. Use multiplication to determine the probability that a one or two appears on the second roll, and an odd number appears on the third roll

1/6

Step-by-step explanation:

Since we don't care what appears on the first roll

P( outcome) = 1

Second roll

P(1 or 2) = number of 1 or 2 / total number of outcomes

              =2/6 = 1/2

Third roll

odd numbers 1,3,5

P( odd number)= number of odd numbers/ total

                          =3/6 =1/2

P( outcome, 1or 2, odd)  = P( outcome) *P(1 or 2) *P( odd number)

                                       = 1* 1/3 * 1/2

                                       = 1/6

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.

the solution is h=10 because you add 9 to each side of the equation.