A psychologist has designed a questionnaire to measure individuals' aggressiveness. suppose that the scores on the questionnaire are normally distributed with a standard deviation of . suppose also that exactly of the scores exceed . find the mean of the distribution of scores. carry your intermediate computations to at least four decimal places. round your answer to at least one decimal place.

        μ = 647.4

Step-by-step explanation:

The question says

"A psychologist has designed a questionnaire to measure individuals' aggressiveness. suppose that the scores on the questionnaire are normally distributed with a standard deviation of . suppose also that exactly of the scores exceed"

And we are told to find the mean of the distribution scores.

Given mean μ = ?

we have from standard normal table that

P(Z > 1.282) = 0.1

Therefore the given Z score of a score of 750 is given thus 1.282.

the z score is given:

x - μ / α = 1.282

750 - μ / 80 = 1.282

Therefore μ = (750 - 80)*1.282 = 647.4

So we have that μ = 647.4

cheers i hope this helped !!!

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.