A quadrilateral has vertices a(-4 -8) b (-2, 34) c(6,12 and d (10, -30). It undergoes the transformation (x, y) to (x/2,y/2). What is it's scale factor?
What are the coordinates of the new vertices?
What is a dilatation?

(Will give

Step-by-step explanation:

scale factor:

1/2

the coordinates of the new vertices are

A (-4/2, -8/2)

A:(-2, -4)

B (-2/2, 34/2)

B: (-1, 17)

C (6/2, 12/2)

C:(3, 6)

D (10/2, -30/2)

D:(5, -15)

I guess the dilation is 2 times bigger?

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right