An inverted conical tank starts the day with 250 ft^3 of crayon wax in it. As the factory commences work, the tank is filled with an additional 40 ft^3 of wax per minute. The height of the wax is modeled by H(V)=3 piV/25. A. Write a function , V(t) to model the volume of wax in the tank after t minutes. B. Find an expression for the composition (HoV)(t) C. The composition in B (above) can be described as the of the wax in terms of

A. V(t) = 40t + 250 B. (HoV)(t) = 24πt/5 + 30π C. The composition in B (above) can be described as the height of the wax in terms of time.

Step-by-step explanation:

A. Let the rate of change of volume V with respect to time be dV/dt = 40 ft³/min

Solving this, V = 40t + C. At the start of the day, that is t = 0, V = 250 ft³

Substituting these values, we have

250 ft³ = 40(0) + C

C = 250 ft³

So, V(t) = 40t + 250

B. Since H(V) = 3πV/25

(HoV)(t) = 3π(40t + 250)/25

= 24πt/5 + 30π

C. The composition in B (above) can be described as the height of the wax in terms of time.

tube or goog would be a great resource to with that question

steve should create a type of business report called a business plan. the correct option among the options that are already given in the question is the last or the fourth option. this business report created by steve will actually influence the investors about investing their money in steve's business. this business report will have all the details about the business, the amount of investment required and the amount of expected profit.