The random numbers below represent 15 trials of a basketball simulation conducted using a spinner numbered 0–8. 76645, 46757, 28334, 81357, 52453, 21761, 51537, 62385, 62135, 16687, 41662, 27135, 45445, 33858, 86427 Let the number 1 represent a 3-point basket and the numbers 2–8 represent 2-point baskets. Based on the simulation, what is the probability that at least one of the next 5 baskets made by the team is a 3-pointer? A. 6/15 B. 8/15 C. 5/15 D. 7/15

Option D.

Step-by-step explanation:

Out of the 15 simulations, the number with a 1 in them is 7. (are the sets of 5 shots that have at least one 3-pointer)

So out of 15 sets, 7 of them have at least one 3-point in them.

the experimental probability is p = 7/15.

So the correct option is D.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.