A rectangular lot is 50 meters wide and 90 meters long. Give the length and the width of another rectangular lot that has the same perimeter but a larger area.

Length = 80 metres and Width = 60 metres.

Step-by-step explanation:

Given

Length = 90m

Width = 50m

Required

Dimension of another rectangle with the same perimeter but larger area;

Perimeter of a rectangle is calculated as thus;

Substitute: Length = 90m and Width = 50m

Area of a rectangle is calculated as thus;

Substitute: Length = 90m and Width = 50m

So, the implication of this question is to get a rectangle whose perimeter is 280m and area is greater that 4500m²

Using trial by error method;

Assume length of a rectangle is 80m;

This means the width must be 60m

Calculating the perimeter

Calculating the area

Since, the area of this rectangle is greater than the area of the previous rectangle. we can adopt this dimension.

Length = 80 metres and Width = 60 metres.

Note: There are other dimensions that have higher area and exact perimeter as the given rectangle in the question;

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1