NFL player Gerald Sensabaugh recorded a 46 inch standing vertical jump at the 2005 NFL Combine, at that time the highest for any NFL player in the history of the Combine. Sensabaugh weighed about 200 lb when he set the record. Part A What was his speed as he left the floor

His speed as he left the floor is 4.83 m/s.

Step-by-step explanation:

Given: 46 inches = 1.1684 m and mass = 200 lb = 90.7185 Kg.

From the third equation of motion under free fall,

  = - 2gs

Where; V is the final velocity (0), U is the initial velocity (unknown), g is the value of gravity - 10 m/ and s is the distance = 1.1684 m.

Then;

0 = - 2gs

= 2gs

   = 2 × 10 × 1.1684

  = 23.368

⇒ U =

       = 4.8340 m/s

The initial velocity, U = 4.83 m/s.

Therefore, his speed as he left the floor is 4.83 m/s.

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step-by-step explanation:

step-by-step explanation:

given expression is .

now we need to simplify the given expression .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

expanding that will give a very very large number so let's keep answer in exponent form.