Who much time would it take for a train accelerating at 21.5 m/s2 to go from 13.2 m/s to 38.9 m/s?

Step-by-step explanation:

v=u+at

38.9=13.2+21.5 t

21.5 t=38.9-13.2

21.5 t=25.7

t=25.7/21.5≈1.195 s

To find the time taken, we use the equation:

v

=Then to find the time taken, we use the equation:

v = u + at

where:

v is the final velocity of the train

u is the initial velocity of the train

a is the train's acceleration

t is the time taken

So, we get:

t = (v-u)/a

t = (38.9 - 13.2)/21.5

t = 25.7/21.5

t = 1.19 seconds

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation:

no

explanation:

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