A ball travels on a parabolic path in which the height (in feet) is given by the expression $-25t^2+75t+24$, where $t$ is the time after launch. At what time is the height of the ball at its maximum?

The height of the ball is at it's maximum 1.5 units of time after launch.

Step-by-step explanation:

Suppose we have a quadratic function in the following format:

If t is negative, the maximu value of h(t) will happen at the point

In this question:

So

Then

The height of the ball is at it's maximum 1.5 units of time after launch.

the answer is 5/3x+7/5y+7

sorry, i don't know i just need points, i'm new here. chao