Solve for x. e^x - e ^ -x / e^x + e ^-x = t

D

Step-by-step explanation:

(eˣ − e⁻ˣ) / (eˣ + e⁻ˣ) = t

Multiply by eˣ/eˣ.

(e²ˣ − 1) / (e²ˣ + 1) = t

Solve for e²ˣ.

e²ˣ − 1 = (e²ˣ + 1) t

e²ˣ − 1 = e²ˣ t + t

e²ˣ = 1 + e²ˣ t + t

e²ˣ − e²ˣ t = 1 + t

e²ˣ (1 − t) = 1 + t

e²ˣ = (1 + t) / (1 − t)

Solve for x.

2x = ln[(1 + t) / (1 − t)]

x = ½ ln[(1 + t) / (1 − t)]

Use log rule.

x = ln(√[(1 + t) / (1 − t)])

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?