HELP EASY PHYSICS QUESTION URGENT :)) A ball is kicked off the ground with a velocity of 15 m/s at an angle of 30° horizontally. What is the horizontal distance the ball travels before returning to the ground?

a.15.5 m

b.17.5 m

c.19.5 m

d.21.5 m

The horizontal distance the ball travels before returning to the ground is 19.5 m

Step-by-step explanation:

Formula of range of horizontal distance =

Where u is the initial velocity

g is gravity

We are given that A ball is kicked off the ground with a velocity of 15 m/s at an angle of 30° horizontally.

So, u = 15 m/s

g = 10

So, the horizontal distance the ball travels before returning to the ground =

Hence The horizontal distance the ball travels before returning to the ground is 19.5 m

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: it's a

step-by-step explanation: