Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to of itself the result is a 15. The modern day equation that models this problem is . What is the solution to the equation?

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.