What is the slope of a line perpendicular to a line that passes through (3,8) and (1,-4)? A. -1/6
B. -1/2
C. 2
D. 6

slope of a line= y²-y¹

x²-x¹

-4-8

1-3

-12

-2

= 6

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

-1/2 +2

step-by-step explanation: