Farmer Smith Jr is putting together fruit baskets. He has 240 oranges and 150 grapefruits. What is the largest number of baskets he can put together so that he can have the same number of oranges in each basket and the same number of grapefruits in each basket? PLEASEE I NEED AN ANSWER

30 baskets

Step-by-step explanation:

To solve this question, we have to find the highest common divisor of 150 and 240

Let's list all the factors of 150;

1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150

Factors of 240 are;

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

Looking at the factors gotten above, the highest common factor to both is 30.

Since there are 240 oranges, it means number of oranges in each basket would be 240/30 = 8 oranges per basket

Also, Since there are 150 grapefruits, it means number of oranges in each basket would be 150/30 = 5 grapefruits per basket

Thus, the oranges and grapefruits would have at most 30 baskets each for them to have the same number of fruits in each of their respective baskets.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;