A marble is selected at random from a jar containing 2 red marbles, 3 yellow marbles, and 6 green marbles. What is the probability that
a) the marble is red?
b) the marble is not yellow?
c) the marble is either red or green?
d) the marble is neither red nor green?

see below

Step-by-step explanation:

2 red marbles, 3 yellow marbles, and 6 green marbles = 11 marbles

a P(red) = red/total = 2/11

b) P(not yellow) = (total - yellow)/total = (11-3)/11 = 8/11

c) P(red or green) = (red or green)/total = (2+6)/11 = 8/11

d) P( not red or green) = P(yellow) = yellow/total = 3/11