Which function has real zeros at x = 3 and x = 7? f(x) = x2 + 4x - 21
O f(x) = x2 - 4x - 21
O f(x) = x2 – 10x + 21
O f(x) = x2 – 10x - 21

all of them will give u zero

but not all of them

in the first one only if you equate x to be 3 that is when it will give u zero

for the second one is only when u equate x to be seven that's when it will be equal to zero

the same thing for the rest!

no problobm

step-by-step explanation:

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )