A sector with a radius of \maroonD{12\,\text{cm}}12cmstart color #ca337c, 12, start text, c, m, end text, end color #ca337c has an area of \goldE{60\pi\,\text{cm}^2}60πcm 2 start color #a75a05, 60, pi, start text, c, m, end text, squared, end color #a75a05. What is the central angle measure of the sector in radians?

9514 1404 393

  5π/6 radians

Step-by-step explanation:

Given:

  a sector with radius 12 cm and area 60π cm²

Find:

  the central angle measure in radians

Solution:

The area is given by the formula ...

  A = (1/2)r²θ

Then the angle is ...

  θ = 2A/r² = 2(60π cm²)/(12 cm)² = 120/144π = 5π/6

The central angle is 5π/6 radians.

the answer is 62.8 cubic units

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol