Prove that there exists a positive integer N such that there are at least 2005 ordered pairs (x, y), of non-negative integers x and y, satisfying x^2 + y^2 = N.

a: 1/6, j: 1/4

step-by-step explanation: you are welcome

the answer is ! ?

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

ur right ive taken the test

step-by-step explanation: