![\left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]](/tpl/images/0684/5477/936c0.png)
![A^T=\left[\begin{array}{ccc}5&3\\2&-1\\\end{array}\right]](/tpl/images/0684/5477/9a043.png)
![\left[\begin{array}{ccc}5&2\\3&-1\\\end{array}\right] \left[\begin{array}{ccc}5&3\\2&-1\\\end{array}\right] =\left[\begin{array}{ccc}5*5+2*2&5*3+2(-1)\\3*5+2(-1)&3*3+(-1)(-1)\\\end{array}\right] =\left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]](/tpl/images/0684/5477/39da3.png)
A.
B.
Mathematics, 12.06.2020 22:57 srgrace9948
Please help! Correct answer only, please!
Find the product A · A^t.
A.
B.
C.
D.
Answers: 2
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Find the product A · A^t.
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