Which is the graph of x – y = 1? A coordinate plane with a line passing through (0, 1) and (1, 0).

A coordinate plane with a line passing through (0, negative 2) and (0, 1).

A coordinate plane with a line passing through (0, negative 1) and (1, 0).

A coordinate plane with a line passing through (negative 1, 0) and (0, negative 1).

Your answer is the third statement, A coordinate plane with a line passing through (0, -1) and (1, 0).

This is because we can rearrange the equation x - y = 1:

x - y = 1

+ y

x = y + 1

- 1

y = x - 1

Now the equation is in the form y = mx + b, we can see that it would represent a line with a slope of 1, that has a y-intercept of -1.

Therefore we know it must go through (0, -1), because that is the point that represents the y-intercept being -1, but it must be the third statement and not the last statement because if we substitute (-1, 0) from the last statement into y = x - 1, we get 0 = -1 - 1, which is false.

I hope this helps! Let me know if you have any questions :)

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5