A rugby player kicks a rugby ball 1 foot above the ground with an initial vertical velocity of 55 feet per second. The function h=-16t^2+55t+1 represents the height of the rugby ball after t seconds. Use a graphing calculator to estimate when the height of the rugby ball is 45 feet

The height of the rugby ball is 45 feet at t = 1.27s and t = 2.17s

Step-by-step explanation:

The height of the ball, in feet, after t seconds, is given by the following equation:

When the height of the rugby ball is 45 feet

This is t for which: h(t) = 45

So

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

In this question:

So

The height of the rugby ball is 45 feet at t = 1.27s and t = 2.17s

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)