Suppose that fish are caught at a lake that contains distinct types of fish. 3xy. x2x3x. 10 5 38 of 848 a. How many different outcomes are possible, where an outcome specifies the numbers of caught fish of each of the types? b. How many outcomes are possible when of the fish caught are trout? c. How many when at least of the are trout? 5 3

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One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to