Please help! I will mark you as and give points. Please show your work The area of Rectangle A is twice the area of Rectangle B. The perimeter of Rectangle A is 20 units greater than the perimeter of Rectangle B. What could the dimensions of the two rectangles be?

size of small rectangle ( 10.15)

size of large rectangle ( 15 , 20 )

Step-by-step explanation:

Let the small rectangle have length x and breadth y . Let the larger rectangle have length x + 5 and breadth y + 5

perimeter of small rectangle = 2 ( x + y )

perimeter of large rectangle = 2 ( x + y + 10 )

= 2( x + y ) + 20

difference = 20

Now area of small rectangle = xy

area of large rectangle = ( x + 5 ) ( y + 5 )

given  ( x + 5 ) ( y + 5 ) = 2 xy

xy + 5 ( x + y ) + 25 = 2xy

5 ( x + y ) + 25 = xy

finding the solution of this equation by trial and error

put x = 10 and y = 15

5 ( 10 + 15 ) + 25 = 150

xy = 10 x 15 = 150

so,

x = 10 , y = 15

size of large rectangle

= 10 + 5 = 15 and

15 + 5 = 20

size of small rectangle ( 10.15)

size of large rectangle ( 15 , 20 )

probably .5

i can on others if necessary.