In this diagram, BAC~ EDF. if the area of BAC = 6 in, what is the area of EDF

9in²

Step-by-step explanation:

Area of a triangle = 1/2 × base × height

For ∆BAC, base = 2in and area = 6in²

Substituting to get the height of the triangle

6 = 1/2 × 2 × h

6 = h

Height = 6in

Since ∆BAC ~ ∆EDF, then they will approximately have the same height. Given base of ∆EDF = 3in

Area of ∆EDF = 1/2bh

Area of ∆EDF = 1/2 × 3 × 6

Area of ∆EDF = 9in²

answer: the answer is 5/22

step-by-step explanation: if you subtract 17 from 22 the answer is 5 therefore the remainder of students are female