What is the radius of the inscribed circle of a triangle with side lengths 9, 13, and 14? Express answer in simplest radical form.

√10

Step-by-step explanation:

The radius of the incircle of a triangle is:

r = √(s (s−a) (s−b) (s−c)) / s

where s is half the perimeter, s = (a + b + c) / 2.

s = (9 + 13 + 14) / 2

s = 18

r = √(18 (18−9) (18−13) (18−14)) / 18

r = √(18 × 9 × 5 × 4) / 18

r = √10

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.