A cylindrical tank is half full of oil The cylinder has a base radius of 100cm The height of the cylinder is 250cm 1 litre =1000cm^3 Round your answer to the nearest litre

3,927 liters.

Step-by-step explanation:

So, in this question we are given the following parameters or information or data which is going to assist us in solving this particular Question;

=> "cylindrical tank is half full of oil."

=> "The cylinder has a base radius of 100cm The height of the cylinder is 250cm"

=> 1 litre =1000cm^3."

Therefore, the formula that we will be making use of in this question is given Below as;

=> Volume = 1/2 × height × (radius)^2 × π.

=> Volume = 1/2 × 250 × 100^2 × π.

Volume = 3926990 cm^3.

Recall that 1 litre =1000cm^3.

Hence, volume = 3,927 liters.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

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step-by-step explanation: