Determine the discriminant for The quadratic equation -3=x^2+4x+1 Based on the discriminant value, how many real numbers solutions does the equation have?
Discriminat = b^2-4ac

(PLEASE HURRY)

D = 0, 1 real solution

Step-by-step explanation:

The first thing you must do it set one side equal to zero. You can do this by adding three to both sides.

You obtain: x^2 + 4x + 4

Using this, we can get a, b, and c and plug it into the discriminant.

a = 1, b = 4, c = 4

The discriminant is: b^2 - 4ac

We can get the discriminant by plugging in a, b and c

D = (4)^2 - 4(1)(4)

D = 16 - 16

D = 0

When D = 0, there is only one real root of the quadratic.

Hope this helped you!