Find the volume of a right circular cone that has a height of 5.6 m and a base with a radius of 16.6 m. Round your answer to the nearest tenth of a cubic meter.

1615.97 m^3

Step-by-step explanation:

V=πr^2 h/3

V= π (16.6)^2 (5.6/3)

V= 1615.97 m^3

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: