The sum of 3 consecutive even integers is 228

Here we will use algebra to find three consecutive integers whose sum is 228. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 228. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 228

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 228

3X + 3 = 228

3X + 3 - 3 = 228 - 3

3X = 225

3X/3 = 225/3

X = 75

Which means that the first number is 75, the second number is 75 + 1 and the third number is 75 + 2. Therefore, three consecutive integers that add up to 228 are 75, 76, and 77.

75 + 76 + 77 = 228

We know our answer is correct because 75 + 76 + 77 equals 228 as displayed above.

74, 76, 78

Step-by-step explanation:

The numbers are even and consecutive so they are 2x, 2x+2 and 2x+4 because any number multiplied by 2 is always even and they are even CONSECUTIVE,. So 2 and 4

Now their sum is given as 228 so,

2x+2x+2+2x+4= 228

6x+6= 228

6x= 228-6= 222

x= 222/6

= 37

So the numbers are:

2x= 37*2= 74

2x+2= 74+2= 76

2x+4= 74+4= 78

srry idk

step-by-step explanation: