Square ABCD has a side length of 1. Point E lies on the interior of ABCD, and is on the line AC such that the length of AE is 1. Find the shortest distance from point E
to a side of square ABCD.

  1 -(√2)/2 ≈ 0.292893

Step-by-step explanation:

The diagonal length AC is √2, so the distance EC is √2 -1. That is the diagonal of the square whose side length is the length of interest. That side length will be (√2)/2 times the length of EC.

  shortest distance from E = (√2 -1)(√2)/2 = 1 -(√2)/2

dont understand

step-by-step explanation:

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5