Can someone please help, i’m struggling. it’s math! explanation needed!!

  exactly two distinct zeros

Step-by-step explanation:

The highest exponent of x is 2, which makes this a quadratic.

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When you compare to the form ...

  y = ax² +bx +c

you can match the coefficients and see that

  a = 1, b = 6, c = 8

These values can be used to compute the "discriminant" (d), which tells you something about the zeros.

  d = b² -4ac

  d = 6² -4·1·8 = 36 -32 = 4

The discriminant is positive, indicating there are exactly two distinct zeros.

More about the discriminant

When d=0, there is exactly one zero. When d is negative, there are two complex zeros.

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

i suppose it should be (y=2x-5)

step-by-step explanation: