At most, Alana can spend $40 on carnival tickets. Ride tickets cost $4 each, and food tickets cost $2 each. Alana buys at least 16 tickets. The system of inequalities represents the number of ride tickets, r, and the number of food tickets, f, she buys. r + f ≥ 16
4r + 2f ≤ 40What is the maximum number of ride tickets she can buy?

The maximum number of ride tickets is 4

Step-by-step explanation:

r = number of ride tickets

f = number of food tickets

r + f ≥ 16

4r + 2f ≤ 40

Using these as equations

f = 16  -r

Using this in the second equation

4r+ 2 (16 -r) = 40

4r +32 -2r = 40

2r +32 = 40

2r = 8

r = 4

The maximum number of ride tickets is 4

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

it's d

step-by-step explanation: