What are the two solutions of x2 - 2x - 4 =-3x + 9? ОО
the y-coordinates of the y-intercepts of the graphs of y = x2 - 2x - 4 and y=-3x + 9
the x-coordinates of the x-intercepts of the graphs of y = x2 - 2x - 4 and y=-3x + 9
the y-coordinates of the intersection points of the graphs of y = x2 - 2x - 4 and y=-3x + 9
the x-coordinates of the intersection points of the graphs of y = x2 - 2x - 4 and y =-3x + 9

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

i belive those are the ones that are under 90 degreese.