Write the rational functions: a) There is a zero at 2, a hole exists at x=-1, vertical asymptote is at x=2, and horizontal asymptote is at y=2 b) There is a zero at -3, a hole exists at x=-4, no vertical asymptotes, and an oblique asymptote at y=x-6 c)The zeros are at -4 and 5 and the vertical asymptote is at x=0. The horizontal asymptote is at y=0 d) the zero is at 2, the vertical asymptote is at x=3 and x=1, and horizontal asymptote is at y=0

The answer is

4335

what's the question?

step-by-step explanation:

there is no question.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.