Rectangle A′B′C′D′ is a dilation of rectangle ABCD. What is the scale factor? Enter your answer in the box. $\text{Basic}$Basic 789÷Divided by456×Multiplied by123-Minus0.,+PlusLeftRightBackspa ce=Equals $x$x$y$y$x^2$x2$\sqrt{ }$√$\frac{x}{ }$ x $x\frac{ }{ }$x $x^{ }$x$x_{ }$x<>±$%$\degree$°:$\left(\ri ght)$()$\abs{ }$$\pi$π$\infty$∞ Note: Images may not be drawn to scale. Rectangle ABCD is shown. Side AB is labeled 2. Side BC is labeled 4. Rectangle A prime B prime C prime D prime is shown. Side A prime B prime is labeled 8. Side B prime C prime is labeled 16.

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)