A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to buy an extended warranty for the car. Let X denote the number of luxury cars sold in a given day, and let Y denote the number of extended warranties sold. The joint probability function of X and Y can be given by the following equation. P(X = 0, Y = 0) =1/6
P(X = 1, Y = 0) =1/12
P(X = 1, Y = 1) =1/6
P(X = 2, Y = 0) =1/12
P(X = 2, Y = 1) =1/3
P(X = 2, Y = 2) =1/6

Required:
Find the mean and variance of X.

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

Mean of X:

Variance of X:

it depends on the weather. because i have flown to seattle when it was pouring down rain and there was one time i flew to ohio when it was snowing hard. whats your situation.

step-by-step explanation:

answer: 20

step-by-step explanation: