FH is the altitude to the hypotenuse EG. what is the length of FH. Really need some help with this!

Option A is correct

Step-by-step explanation:

Given: FH is the altitude to the hypotenuse EG

To find: length of FH

Solution:

According to Pythagoras theorem, square of hypotenuse is equal to sum of squares of other two sides.

In ,

So,

Put EH = 6 units and EF = 7 units

Option A is correct

Take square root on both sides

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx